Please, see the offered decision: 1) common equation for lines is y=kx+b. If k₁=k₂ (for line 1 and line 2) ⇒ 'line 1' || 'line 2'. 2) for line 3x+5y=6 k= -3/5. It means (according to item 1) for unknown line k is the same (-3/5). 3) using points (0;3) it is easy to find parameter b (x=0, y=3) via y=kx+b: 3=0*(-3/5)+b ⇔ b=3. 4) finaly (k=-3/5; b=3):