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nasty-shy [4]
3 years ago
14

Look at the figure shown below: A triangle RPQ is shown.

Mathematics
2 answers:
Goryan [66]3 years ago
7 0

Answer:

28:35  

Explanation:

Given the reason for step 5, Corresponding sides of similar triangles  are in proportion, we are looking for sides that will be corresponding to 2x+28 and 95.  2x+28 is the length of QP and 95 is the length of PR.  The matching option in our list is 28:95, because 28 is the length of SP and 35 is the length of PT.  

yulyashka [42]3 years ago
3 0

Answer:  The correct option is (B) 28 : 35.

Step-by-step explanation:  A triangle PQR is shown in the given figure. Rita is writing statements to prove that if segment ST is parallel to segment RQ, then x = 24.

Also, given that

PS = 28, SQ = 2x, PT = 35  and  TR = 60.

We are to select the correct proportion that completes statement 5.

The statements are as follows:

(1). Given that Segment ST is parallel to segment QR.

(2). ∠QRT is congruent to ∠STP [Corresponding angles formed by parallel lines and their transversal are congruent].

(3). ∠SPT is congruent to ∠QPR [Reflexive property of angles].  

(4). So, Δ SPT is similar to ΔQPR [Angle-Angle Similarity Postulate].  

The next (fifth) step will be

(5) We know that the corresponding sides of similar triangles are proportional, so we must have

\dfrac{PQ}{PS}=\dfrac{PR}{PT}\\\\\\\Rightarrow \dfrac{2x+28}{28}=\dfrac{35+60}{35}\\\\\\\Rightarrow \dfrac{2x+28}{28}=\dfrac{95}{35}\\\\\\\Rightarrow \dfrac{2x+28}{95}=\dfrac{28}{35}\\\\\\\Rightarrow (2x+28):95=28:35.

Thus, Rita can use the proportion 28 : 35 to complete statement 5.

Option (B) is correct.

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Answer:  f(x) = 1.5*sin(x*2*pi/0.0038s)

Step-by-step explanation:

A sine function is:

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c is a constant that depends on the frequency.

f is a phase.

As there is no mention of a phase, we can assume f = 0.

Then our function is:

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now let's find the value of c.

We know that the frequency is 262hz.

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Then we have that:

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sin(0) = sin(2*pi)

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Then the function is:

f(x) = 1.5*sin(x* 2*pi/0.0038s)

3 0
3 years ago
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In rectangle PQRS, PR = 11x – 20and QS = x + 160.
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Answer:

\large \boxed{1.\, x = 18; 2.\, 178}

Step-by-step explanation:

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\begin{array}{rcll}11x - 20 & = & x + 160 & \\11x &= & x + 180 & \text{Added 20 to each side}\\10x & = & 180 & \text{Subtracted x from each side}\\x& = & \mathbf{18} &\text{Divided each side by 10}\\\end{array}\\\large \boxed{\mathbf{x = 18}}

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