Answer:
The least possible score Pia can earn on the fourth assignment and still be able to finish the week with an average score of 90 on all five assignments is 86
Step-by-step explanation:
The information given are;
Pia's scores in the first three assignments = 87, 85, and 92
The question asks to find upon finishing the week's five assignments the least possible score that Pia can earn on the fourth assignment and still be able to have an average score of 90 on all five assignments
Let the least score required to have an average score of 90 on all five assignments be X
If X is the least score to obtain an average of 90 for the five assignments, then fifth assignment score, will be maximum possible score obtainable to allow the attainment of the average score of 90 which is 100, which gives;
(87 + 85 + 92 + X + 100)/5 = 90
∴ 5 × 90 = 450 = 87 + 85 + 92 + X + 100 = 364 + X
X = 450 - 364 = 86
Therefore, the least possible score Pia can earn on the fourth assignment and still be able to finish the week with an average score of 90 on all five assignments = 86.
Answer:
average = 52, 100 on fourth test
Step-by-step explanation:
average = 75 + 74 + 71 = 156 / 3 = 52
average = 52
b grade = 75 + 74 + 71 + 100 = 320 / 4 = 80
to get a b grade she must get 100 on her fourth test
Answer:
You have to be specific. Do you have a picture that you can send to us so we can help you?
Step-by-step explanation:
Answer:
5182
Step-by-step explanation:
To figure out the mean of a number, you must add all of the numbers together and divide by the amount of numbers you added up.
To find the total sum, we just need to reverse this process.
We are already given the final number so all we have to do is multiply the mean by 100 and we have our answer of 5182.
Hope this helps :D