Using the hypergeometric distribution, it is found that there is a 0.0455 = 4.55% probability that both light bulbs failed the test.
The bulbs are chosen without replacement, and this is why the <u>hypergeometric distribution</u> is used to find the probability.
Hypergeometric distribution:
The parameters are:
- x is the number of successes.
- N is the size of the population.
- n is the size of the sample.
- k is the total number of desired outcomes.
In this problem:
- 12 bulbs, thus
- 3 failed the test, thus .
- 2 are selected, thus .
The probability that <u>both failed the test</u> is P(X = 2), thus:
0.0455 = 4.55% probability that both light bulbs failed the test.
A similar problem is given at brainly.com/question/24826394
Answer:
You can prove them to be congruent.
Step-by-step explanation:
You would use the SSS Postulate. This means Side Side Side.in the figure shown you can see sides AB and BC have one line crossing them making them equal. Same with side AD and CD. With side BD they are congruent because they are equal in size and share both triangles.
Hope this helps.
F(x) = 4 - 2x Domain = x = -4, 0, 5
f(x) = 4 - 2(-4) = 4 - (-8) = 12
f(x) = 4 - 2(0) = 4 - 0 = 4
f(x) = 4 - 2(5) = 4 - 10 = -6
f(x) = 12, 4, -6
The range is C.
Step-by-step explanation:
<u>If you are looking for values of y, they are:</u>
- x = - 2 ⇒ y = 2*(-2) = - 4
- x = - 1 ⇒ y = 2*(-1) = - 2
- x = 0 ⇒ y = 2*0 = 0
- x = 1 ⇒ y = 2*1 = 2
- x = 2 ⇒ y = 2*2 = 4