The formula for energy of motion is KE = .5 x m x v^2
Ke= Kinetic Energy in Joules
m = Mass in Kilograms
v = Velocity in Meters per Second
Answer:
D.
Explanation:
To solve the problem it is necessary to apply the concepts of Destructive and constructive interference. The constructive interference in tin film is given by
Where,
t = thickness
Wavelenght
m= is an integer
n= film/refractive index
We use this equaton because phase change is only present for gasoline air interface, but not at the gasoline-water interface. <em>The minimum t only would be when the value of m=0 then</em>
Therefore the correct answer is D. The minimum thickness of the film to see ab right reflection is 100nm
The Lorentz force exerted on the particle due to the magnetic field provides the centripetal force that keeps the particle in circular motion:
where
m is the particle mass
v is its velocity
r its orbital radius
q its charge
B the magnetic field intensity
and where we neglected the factor
in the Lorentz force formula because the particle is traveling perpendicular to the magnetic field, so
.
Re-arranging the formula, we get
(1)
The problem gives us all the data about the particle and the magnetic field:
(we are only interested in the magnitude of the charge)
And by plugging these numbers into eq.(1), we find the radius of the orbit
Answer:
η = 40 %
Explanation:
Given that
Qa ,Heat addition= 1000 J
Qr,Heat rejection= 600 J
Work done ,W= 400 J
We know that ,efficiency of a engine given as
Now by putting the values in the above equation ,then we get
η = 0.4
The efficiency in percentage is given as
η = 0.4 x 100 %
η = 40 %
Therefore the answer will be 40%.
Answer:
A)
ms⁻¹
B)
J
C)
i)
ms⁻¹
ii)
ms⁻¹
iii)
ms⁻¹
Explanation:
A)
= velocity of center of hoop
w = angular speed of the hoop = 3 rads⁻¹
d = diameter of the hoop = 2.20 m
radius of the hoop is given as
velocity of center of hoop is related to angular velocity by the relation given as
inserting the values
ms⁻¹
B)
= moment of inertia of hoop
= mass of the hoop = 2.30 kg
= radius of hoop = 1.10 m
Moment of inertia of the hoop is given as
kgm²
Total kinetic energy is given as
J
C)
i)
= velocity at highest point
velocity at highest point is given as
ms⁻¹
ii)
= velocity at bottom
velocity at bottom point is given as
ms⁻¹
iii)
= velocity at right
velocity at right is given as
ms⁻¹