Answer:
WU = (14√13)/13 ≈ 6.6564
Step-by-step explanation:
Call the incenter of ∆KWU point A. Call the center of circle ω2 point B.
Then ∠KWA has half the measure of arc WA. ∠AWU is congruent to ∠KWA, so also has half the arc measure. That is, ∠KWU has the same measure as arc WA and ∠KBW.
KB is a perpendicular bisector of chord WU, so ∆KWB is a right triangle, of which WU is twice the altitude to base KB.
The length of KB can be found several ways. One of them is to use the Pythagorean theorem:
KB² = KW² +WB² = 4² +6² = 52
KB = √52 = 2√13
The area of triangle KWB is ...
area ∆KWB = (1/2)KW·WB = (1/2)(4)(6) = 12 . . . . square units
Using KB as the base in the area calculation, we have ...
area ∆KWB = (1/2)(KB)(WU/2)
12 = KB·WU/4
WU = 48/KB = 48/(2√13) = 24/√13
WU = (24√13)/13 ≈ 6.6564
X to the power of 2 + 4x +5
<span>The base of an exponential function can only be a positive number: it is TRUE
Proof
for all value of x, e^x always positive</span>
Answer:
10 and 6
Step-by-step explanation:
2 can go into both 6 and 10 and 6 and 10 are multiples of 60
Answer:
a =18
Step-by-step explanation:
The two angles are vertical angles and vertical angles are equal
6a +11 = 2a+83
Subtract 2a from each side
6a-2a +11 = 2a-2a+83
4a +11 =83
Subtract 11 from each side
4a +11 -11 = 83-11
4a = 72
divide each side by 4
4a/4 = 72/4
a =18