Answer the term solenoid refers to a long, thin loop of wire, often wrapped around a metallic core, which produces a magnetic field when an electric current is passed through it. Solenoids are important because they can create controlled magnetic fields and can be used as electromagnets
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Answer:
The car must travel 51.34 m for its speed to reach 2.7 m/s
Explanation:
Mass of car = 2.9 x 10³ kg
Forward force = 1148 N
Resistive force = 941 N
Total force = 1148 - 941 = 207 N
We know
Force = Mass x Acceleration
207 = 2.9 x 10³ x Acceleration
Acceleration = 0.071 m/s²
Now we have equation of motion, v² = u² + 2as
Initial velocity, u = 0 m/s
Final velocity, v = 2.7 m/s
Acceleration, a = 0.071 m/s²
Substituting
v² = u² + 2as
2.7² = 0² + 2 x 0.071 x s
s = 51.34 m
The car must travel 51.34 m for its speed to reach 2.7 m/s
Answer:
Between 2.0 s and 4.0 s (B and C)
Between 5.0 s and 8.0 s (D and E)
Between 10.0 s and 11.0 s (F and G)
Explanation:
The graph shown in the figure is a velocity-time graph, which means that:
- On the x-axis, the time is plotted
- On the y-axis, the velocity is plotted
Therefore, this means that the object is not moving when the line is horizontal (because at that moment, the velocity is constant, so the object is not moving). This occurs in the following intervals:
Between 2.0 s and 4.0 s (B and C)
Between 5.0 s and 8.0 s (D and E)
Between 10.0 s and 11.0 s (F and G)
From the graph, it would be possible to infer additional information. In particular:
- The area under the graph represents the total distance covered by the object
- The slope of the graph represents the acceleration of the object
Answer:
10 days
Explanation:
The half-life of a radioactive sample is the time taken for half of the sample to decay.
In the diagram, the half-life corresponds to the time after which the % of cobalt-57 has halved. We can observe the following:
At t=10 days, the % of Co remaining is approximately 45%
At t=20 days, the % of Co remaining is approximately 22%
This means that the sample of cobalt-57 has halved in 10 days, so the half-life of cobalt-57 is 10 days.
Answer:
The compression in the spring is 9.64 meters.
Explanation:
Given that,
Mass of the train, m = 6251 kg
Speed of the train, v = 27 m/s
Spring constant of the spring, k = 48979 N/m
We need to find the compression in the spring when it comes to rest. It is a case of conservation of energy. The kinetic energy of the train is converted to elastic potential energy. So,
x is compression in spring
So, the compression in the spring is 9.64 meters.