Answer:
In these situations, the median is generally considered to be the best representative of the central location of the data. The more skewed the distribution, the greater the difference between the median and mean, and the greater emphasis should be placed on using the median as opposed to the mean.
5x - 1 = 6x - 3
6x - 5x = -1 + 3
x = 2
LA = MA = NA = 5(2) - 1 = 10 - 1 = 9
answer is B. 9 units
Answer:
Answer is 2×c + log [10^{a} + 10^{b}] +a
Step-by-step explanation:
log 2 = a ,log 3 = b , log 7 = c
Using formula
<em>log d×e = log d + log e</em>
<em> log d^{a} = a×log d</em>
<em> log 5 = log [10^{a} + 10^{b}]</em>
log 490 in terms of a , b and c and you can have integer coefficients
log 490
= log 7^{2}×5×2
= 2×log 7 + log 5 + log 2
= 2×c + log [10^{a} + 10^{b}] +a
Answer is 2×c + log [10^{a} + 10^{b}] +a
The answer is V≈ 463.25 m³
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Answer:
2 is the answer
Step-by-step explanation: