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According to the statement of the question, we can assemble the following system of equation
X = 7 + 3Y i
X + Y = 75 ii
So, multiplying ii by -1 and adding with i
X = 7 + 3Y
- X - Y = - 75
- Y = 7 + 3Y - 75
4Y = 68
Y = 17
for X we will use ii:
X + Y = 75
X + 17 = 75
X = 58
The smaller number is: 17
17/5 = 5/5 + 5/5 + 5/5 + 2/5 = 3 + 2/5
<span>The simplest mixed number for 17/5 is 3 2/5.</span>
Answer:
7x^2 + 4x + 5
Step-by-step explanation:
hope that work
Answer: 3
<u>Explanation:</u>
Since we want the least number of integers, divide by the largest integer (9).
2018 ÷ 9 = 224 remainder 2
So, N = 2999...999 <em>(there are 224 of the 9's) </em>
Thus, N + 1 = 2999...999 + 1 <em>(there are 224 of the 9's) </em>
<em> </em>= 3000...000 <em>(there are 224 of the 0's) </em>
The sum of the digits is: 3 + 0 + ... + 0 <em>(there are 224 of the 0's) </em>
= 3