Drag Force = bv^2 = ma; a = g = 9.81 m/s^2
b = mg/v^2 = (0.0023×9.81)/(9.4^2)
b = 0.000255
Answer:
The speed of the plank is 81.68 m/s
Explanation:
Given that,
Speed of bullet = 152 m/s
Speed of wood = 128 m/s
Speed of another bullet = 97 m/s
We need to calculate the speed of plank
Using conservation of momentum
Where,
u = initial velocity
v = final velocity
....(I)
....(II)
From equation(I) and equation(II)
Hence, The speed of the plank is 81.68 m/s
Proxima Centauri is approximately 4x1013 kilometers away from the sun. Which multiplies up to 40,000,000,000,000 km. Hope I helped! Thanks for asking us here at Brainly! Feel free to ask more questions at anytime!
Answer:
(a) 2.512 m
(b) 144 m
(c) 904.32 m
Explanation:
radius, r = 4.8 m
(a) for 30 degree
As we know that in 360 degree it rotates a complete round that means circumference.
In 360 degree, it rotates = 2 x π x r
in 30 degree, it rotates = 2 x π x r x 30 / 360
= 2 x 3.14 x 4.8 x 30 / 360
= 2.512 m
(b) for 30 rad
As we know that in one complete rotation, it rotates by 2π radian.
so,
for 2π radian it rotates = 2 x π x r
for 30 radian, it rotates = 2 x π x r x 30 / 2 π = 144 m
(c) For 30 rev
In one complete revolution, it travels = 2 x π x r
in 30 rev, it travels = 2 x π x r x 30 = 2 x 3.14 x 4.8 x 30 = 904.32 m