Answer:
0.26087 rad/s
Explanation:
mass of the child (m) = 40 kg
velocity (v) = 3 m/s
distance (r) = 1.5 m
moment of inertia (I) = 600 kg.m^{2}
rotational momentum of the child = Iω
where
- moment of inertia of the child (I) = = 40 x 1.5 x 1.5 = 90 kg/m^{2}
- angular velocity (ω) = velocity / distance = 3 / 1.5 = 2 rad/s
rotational momentum of the child = Iω = 90 x 2 = 180 kg/s
from the conservation of momentum the initial momentum of the child must be the same as the final momentum of the child
initial momentum of the child = final momentum of the child
180 = (90 + 600) ω
180 = 690 ω
ω = 180 / 690 = 0.26087 rad/s
its 55 :) have a great day queen/king/whatever gender you are
Answer:
Explanation:
The formula that relates the luminosity of a star (L) to its radius (R) and the temperature (T) is
For star B, we can write:
For star A, we have
So the luminosity of star A is
28 degrees celsius converts to 82.4 degrees in Fahrenheit :)
Answer:
40000N
Explanation:
Given parameters:
Mass of the car = 1000kg
Velocity of the car = 20m/s
Time taken = 0.5s
Unknown:
Force on the car = ?
Solution:
According to Newtons second law of motion:
F = m a
F is the force
m is the mass
a is the acceleration
F = m
Change in velocity = 0 - 20 = -20m/s
F = 1000 x = -40000N
The force on the car is 40000N