It is suitable to start with a "let ..." statement defining the meaning of the variable(s) you use in the problem. Here, problems 1, 2, 4 have you multiply the variable by some constant representing a unit rate. In problem 3, you additionally have to perform some math to find an amount remaining.
1) Let s represent the number of shirts purchased at 24.95 each. Then the total cost in dollars is ...
... 24.95s
2) Let t represent the number of trees watered. Then the total number of gallons of water used is ...
... 30t
3) Let q represent the quantity of marbles given away. Then the number remaining is ...
... 48 - q
4) Let p represent the number of pairs of pants purchased at 32.95 each. Then the total cost in dollars is
... 32.95p
The picture you posted did not show ?
Well then let's try and find the pattern!
When we add 1 through 10, we can also say that we're adding all of these values together:
1 + 10 = 11
2 + 9 = 11
3 + 8 = 11
4 + 7 = 11
5 + 6 = 11
So we can also say that this is like multiplying 11 * 5 = 55
If we add up to 100, we can see that it's like multiplying 101 * 50 = 5050
From this, we can get an equation:
(x + 1) * (x/2)
So let's plug in 10000 into this equation:
(x + 1) * (x/2)
(10000 + 1) * (10000/2)
10001 * 5000 = 50005000
Answer:
C 50005000
Answer:
Lisa is not right.
Step-by-step explanation:
The equation Lisa is solving is x+6=8+x
The solution for the given value will be the value of x.
To solve for x we isolate the x term that is bring both x on one side of the equal sign.
Subtracting x both sides we have:
x-x+6=8+x-x
The x on both sides gets cancel and hence there is no value of x that will satisfy the equation x+6=8+x.
So Lisa solution is not right.
For this case we must find the x-intercepsts of the following function:
For this we do , that is: . So:
The values of "x" that comply with equality are:
Thus, the x-intercepsts of the function are:
Answer: