To draw the median of the triangle from vertex A, the mid point of BC must be determined. The median of the vertex A is given at (-1/2, 1). See explanation below.
<h3>How you would draw the median of the triangle from vertex A?</h3>
Recall that B = (3, 7)
and C = (-4, -5).
- Note that when you are given coordinates in the format above, B or C = (x, y)
- Hence the mid point of line BC is point D₁ which is derived as:
D₁ , - hence, the Median of the Vertex A = (-1/2, 1).
Connecting D' and A gives us the median of the vertex A. See attached graph.
<h3>What is the length of the median from C to AB?</h3>
Recall that
A → (4, 2); and
B → (3, 7)
Hence, the Midpoint will be
,
→
Recall that
C → (-4, 5)
Hence,
=
Simplified, the above becomes
= √(586)/2)
= 24.2074/2
= 12.1037
The length of the Median from C to AB ≈ 12
Learn more about Vertex at;
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If you would like to solve the equation 0 = 1/2 - 2 * y, you can calculate this using the following steps:
0 = 1/2 - 2 * y
2 * y = 1/2 /2
y = 1/2 / 2
y = 1/4
The correct result would be 1/4.
The line tht has a slope of 0 is y=x
Note! Every triangle must add up to 360°
1. x =
(×+29°) + (x+19°) + 84° = 360°
x + x + 29° + 19° + 84°= 360°
2x + 48° + 84°= 360°
2x + 132° = 360°
2x = 228°
x = 114°
m(angle)A =
(x+29°)
(114°+29°)=143°
m(angle)B=
(x+19°)
(114°+19°)=133°
3. is a bit different
(3x+6)° = (8x+3)°+130°
-5x+6° = 3° + 130°
-5x = 133° - 6°
-5x = 127°
x = -25.4°
m(angle)A=
(3x+6)°
3×(-25.4)+6= -70.2°
m(angle)DBE=
(8x+3)°=
8(-25.4)+3= -200.2°
I only did 1. and 3. for examples now, but if you need help with anymore just ask!
Hey there! :)
Answer:
1.
Step-by-step explanation:
If a line has the equation y = x + 6, a parallel line would contain the same slope.
In the equation y = x + 6, there is no coefficient, or slope. This means that the slope, or m = 1.
Thus, a parallel line would contain an equivalent slope, making the slope of the parallel line = 1.