Answer:
<em>C</em> C2H5OH = 7.598 molal
Explanation:
- molality (m) C2H5OH = n C2H5OH / Kg H2O
∴ V C2H5OH = 50.0 mL
∴ V H2O = 112.7 mL
∴ T = 20 °C
∴ δ C2H5OH (20°C) = 0.789 g/mL
∴ δ H2O (20°C) = 1.00 g/mL
∴ Mw C2H5OH = 46.0684 g/mol
⇒ n C2H5OH = (50.0 mL)×(0.789 g/mL)×(mol/46.0684 g) = 0.8563 mol
⇒ mass H2O = (112.7 mL)×(1.00 g/mL)×(Kg / 1000 g) = 0.1127 Kg
⇒ <em>C</em> C2H5OH = 0.8563 mol C2H5OH / 0.1127 Kg H2O
⇒ <em>C</em> C2H5OH = 7.598 molal
The answer is either a superphosphate or a triple superphosphate
- Due to the inability of the reaction to take place, the yield of 1-Bromobutane would drop.
- Since 1-Butanol won't react with the additional sodium bromide, bromination won't happen.
- If water had been supplied, the equilibrium would have shifted extremely far to the left, preventing the reactants from interacting with the acid and favoring the yield of 1-bromobutane instead.
<h3>What is Bromination?</h3>
- When a substance undergoes bromination, bromine is added to the compound as a result of the chemical reaction.
- After bromination, the result will have different properties from the initial reactant.
- For example, an alkene is brominated by electrophilic addition of .
- Benzene ring bromination by electrophilic aromatic substitution.
Learn more about Bromine here:
brainly.com/question/862562
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