Answer depends how many people are there and once u find out mulitply it by 3 and boom theres ur answer but for the buns atfer u multiply it by 3 multiply it by 2
Step-by-step explanation:
Answer:
(a). Weight of the bag of organic apples for advertising = 5 pound
Cost of the advertisement of 5 pound bag of organic apples = $13.95
Now, to find the unit rates :
Cost of advertising 5 pound bag of organic apple = $13.95
Hence, unit rate of advertising 1 pound of organic apples = $2.79
$13.95 is charged for advertisement of 5 pound of organic apples
Hence, one unit or $1 is charged for advertisement of 0.36 pounds of organic apples.
(b) Cost of 5 pound is given to be $13.95
So, the rate which is typically used in the given problem is : Dollars per pound.
Triangle on the right is 45 45 90 right triangle
Ratio of leg : hypo = a :a√2
Given hypo = 6 so leg = 3√2
As you know leg of triangle on the right is the hypo of the triangle on the left
Triangle on the left is 30 60 90 right triangle
Ratio of short leg :hypo = a : 2a
You know hypo = 3√2 so leg x = (3√2 ) / 2 = 3√2 / 2
Answer is A. 3√2 / 2
Hi! This might be long but I hope it helps!
1. 115. If q=4, then the equation tells us that 0.1d+(0.25)⋅4=12.5. Subtracting 1 from both sides gives 0.1d=11.5, so d=115.
2. 100. If q=10, then the equation tells us that 0.1d+(0.25)⋅10=12.5. Subtracting 2.5 from both sides gives 0.1d=10, so d=100.
3. Yes. If you know the number of quarters, then you can determine the number of dimes from the equation. We can even write the equation in a way that shows this: d=125−2.5q. The expression 125−2.5qrepresents the output—it is the rule that determines the output d from a given input q.
The trigonometric identity (cos⁴θ - sin⁴θ)/(1 - tan⁴θ) = cos⁴θ
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How to solve the trigonometric identity?</h3>
Since (cos⁴θ - sin⁴θ)/(1 - tan⁴θ) = [(cos²θ)² - (sin²θ)²]/[1 - (tan²θ)²]
Using the identity a² - b² = (a + b)(a - b), we have
(cos⁴θ - sin⁴θ)/(1 - tan⁴θ) = [(cos²θ)² - (sin²θ)²]/[1 - (tan²θ)²]
= (cos²θ - sin²θ)(cos²θ + sin²θ)/[(1 - tan²θ)(1 + tan²θ)] =
= (cos²θ - sin²θ) × 1/[(1 - tan²θ)sec²θ] (since (cos²θ + sin²θ) = 1 and 1 + tan²θ = sec²θ)
Also, Using the identity a² - b² = (a + b)(a - b), we have
(cos²θ - sin²θ) × 1/[(1 - tan²θ)sec²θ] = (cosθ - sinθ)(cosθ + sinθ)/[(1 - tanθ)(1 + tanθ)sec²θ]
= (cosθ - sinθ)(cosθ + sinθ)/[(cosθ - sinθ)/cosθ × (cosθ + sinθ)/cosθ × sec²θ]
= (cosθ - sinθ)(cosθ + sinθ)/[(cosθ - sinθ)(cosθ + sinθ)/cos²θ × 1/cos²θ]
= (cosθ - sinθ)(cosθ + sinθ)cos⁴θ/[(cosθ - sinθ)(cosθ + sinθ)]
= 1 × cos⁴θ
= cos⁴θ
So, the trigonometric identity (cos⁴θ - sin⁴θ)/(1 - tan⁴θ) = cos⁴θ
Learn more about trigonometric identities here:
brainly.com/question/27990864
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