The line containing the vector <em>q</em> can be obtained by scaling <em>q</em> by an arbitrary scalar <em>t</em>. To make this line pass through the point <em>p</em>, translate this line by a vector <em>p</em> pointing from the origin to <em>p</em>.
So the line we want has equation
<em>r</em>(<em>t</em>) = <em>q</em><em>t</em> + <em>p</em> = (14, -8)<em>t</em> + (-4, 12) = (14<em>t</em> - 4, 12-8<em>t</em>)
where <em>t</em> is any real number.
Answer: Deena is correct
Step-by-step explanation:
Deena is correct because the number doesn't terminate nor does it repeat. If it does not repeat or terminate it means it is irrational.
Answer:
6
Step-by-step explanation:
Don't get me wrong, I am not exactly sure but I believe it is supposed to be 75$.