The number of days that the eggs took in hatching is 54 days.
Given that mean is 50, standard deviation is 2 and confidence level is 95% and sample size is 35.
We are required to find the number of days it took to hatch the eggs.
We have to apply the z statistics because sample size is greater than 30.
Z=(X-μ)/σ, in which μ is mean and σ is standard deviation.
Z score for the confidence level 95% is 1.96.
1.96=(X-50)/2
3.92=X-50
X=50+3.92
X=53.92
X=54 (After approximation)
Hence the number of days that the eggs took in hatching is 54 days.
Learn more about z statistics at brainly.com/question/25638875
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Answer: -2 and 4
Step-by-step explanation:
Let
.

Answer:
D 98 inches
Step-by-step explanation:
Answer:
The required probability is 0.0155.
Step-by-step explanation:
We are given that the one-year survival rate for pancreatic cancer is 20%.
Of 12 people diagnosed with pancreatic cancer at one hospital, 6 survived one year.
The above situation can be represented through binomial distribution;

where, n = number of trials (samples) taken = 12 people
r = number of success = 6 survived
p = probability of success which in our question is probability of
one-year survival rate for pancreatic cancer, i.e; p = 20%
Let X = <u><em>Number of people survived one year</em></u>
So, X ~ Binom(n = 12 , p = 0.20)
Now, the probability that 6 survived one year is given by = P(X = 6)
P(X = 6) =
=
= <u>0.0155</u>