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frez [133]
4 years ago
7

An object can be moving from 10 seconds and still have zero displacement true or false

Physics
1 answer:
Tasya [4]4 years ago
8 0

It is True :) :( :) :(


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the headlamp of a car takes a current of 0.4 ampere from a 12 volt supply. the energy produced in 5 minutes is​
serg [7]
Voltage (V) = 12 v
Current (I) = 0.4 A
Time (t) = 5min = 300sec

Power = Voltage x Current
= V x I
= 12 x 0.4
Power = 4.8wats = 4.8W

Power = Energy / Time
Energy = Power x Time
Energy = 4.8 x 300
Energy = 1440 joules
Final answer : 1440J
5 0
2 years ago
Forces cause changes to the motion of objects. Name a force and describe two changes it makes.
otez555 [7]
Sliding and Static.

Would be the right one here.
3 0
4 years ago
Explain why a 5eV photon of light cannot be absorbed or emitted by the hydrogen atom
sweet [91]

Answer:

None of the transitions in the hydrogen atom corresponds to a photon energy of 5eV hence no photon of this energy is absorbed or emitted by the hydrogen atom.

Explanation:

Electrons in a hydrogen atom must be in one of the allowed energy levels. If an electron is in the first energy level, it must have exactly -13.6 eV of energy. If it is in the second energy level, it must have -3.4 eV of energy and so on.

If the electron wants to jump from the first energy level, n = 1, to the second energy level n = 2. The second energy level has higher energy than the first, so to move from n = 1 to n = 2, the electron needs to gain energy. It needs to gain (-3.4) - (-13.6) = 10.2 eV of energy to be excited to the second energy level.

The step from the second energy level to the third is much smaller. It takes only 1.89 eV of energy for this excitation to take place. It takes even less energy to excite electrons in hydrogen from the third energy level to the fourth, and even less from the fourth to the fifth.

None of these transitions in the hydrogen atom corresponds to a photon energy of 5eV hence no photon of this energy is absorbed or emitted by the hydrogen atom.

5 0
3 years ago
A pupil adds 37g of ice at 0°C to 100g of water at 30°C. The final temperature of the water and melted ice is 0°C. no heat is lo
mojhsa [17]

Answer:

The specific latent heat of ice is approximately 341 J/g

The correct option is;

b) 341 J/g

Explanation:

The given parameters are;

The mass of ice the pupil adds to the water, m₁ = 37 g

The initial temperature of the ice, T₁ = 0°C

The mass of the water to which the ice is added, m₂ = 100 g

The initial temperature of the water, T₂₁ = 30°C

The final temperature of the water and the melted ice, T₂₂ = 0°C

The specific heat capacity of the water, c₂ = 4.2 J/(g·°C)

By the principle of conservation of energy, we have;

The heat gained by the ice = The heat lost by the water = ΔQ₂

Given that the ice is only melted with no change in temperature, we have;

The heat gained by the ice = The latent heat needed for melting the ice

ΔQ₂ = m₂ × c₂ × (T₂₂ - T₂₁) = 100 × 4.2 × (0 - 30) = -12,600 J

The heat gained by the ice = m₁ × L_f

Where;

L_f represents the specific latent heat of fusion of ice;

We have;

12,600 = 37 × L_f

L_f = 12,600/37 = 340.54 J/g ≈ 341 J/g

The specific latent heat of fusion of ice = L_f ≈ 341 J/g.

5 0
3 years ago
What is the name of the kind of stretch that involves stretching as far as you can and then holding for 10-30 seconds
Dmitriy789 [7]

Answer:

Static stretching.

Explanation:

It is static stretching because it is a form of stretching which u can do actively for a period of time and you hold position for about 30 to 60 seconds which allow the muscles and connective tissues to lengthen. It is done after work out with out movement in order to loosen up muscles so as to gain flexibility.

7 0
3 years ago
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