The radius going through the tangent point is perpendicular to the tangent line, so ΔQRT is a right triangle.
QT²=QR²+RT²
QR and QS are both radii, so QR=QS=15
QT²=15²+36²
QT=39
The ANWSER is B hope this helps
Answer:
Yes
Step-by-step explanation:
If you divide their time by 100 you will get the amount of time it takes the student to run 1 meter.
Ex. Time is 20 seconds.
20/100
0.2 meters/second
Answer:
4n^2 - 3n + 7
Step-by-step explanation:
Area is length x width. If the width is 5n^2, we have to factor that out of each variable of the area
Area: 20n^4 - 15n^3 + 35n^2
20n^4 divided by 5n^2 = 4n^2
-15n^3 divided by 5n^2 = -3n
35n^2 divided by 5n^2 = 7
So the length is 4n^2 - 3n + 7
Answer:
24.5
Step-by-step explanation:
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