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Reika [66]
4 years ago
15

What is the gcf In this problem

Mathematics
1 answer:
Sergeeva-Olga [200]4 years ago
6 0
The GCF of 88r^{18} \; 24r^{13} would be 8r^{13}
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Ahsan
NikAS [45]

It is number 1 and number 2 because the equation is 242× 62 and Number 1 and 2 are just breaking it down

7 0
3 years ago
Blairs new computer cost 5$ less than twice the cost og her old computer. Her new computer cost 709$. how much did blairs old co
Phantasy [73]

The cost of old computer is $ 357

<em><u>Solution:</u></em>

Let "x" be the cost of old computer

From given,

Cost of new computer = $ 709

Blairs new computer cost 5$ less than twice the cost of her old computer

Therefore,

Cost of new computer = twice the cost of old computer - 5

Cost of new computer = 2x - 5

709 = 2x - 5

2x = 709 + 5

2x = 714

Divide both sides by 2

x = 357

Thus the cost of old computer is $ 357

8 0
4 years ago
What is the inequality x+5&lt;2
Vlad [161]

Answer:

x < - 3

Step-by-step explanation:

Given

x + 5 < 2 ( subtract 5 from both sides )

x < - 3

8 0
4 years ago
Read 2 more answers
The tread life of a particular brand of tire is a random variable best described by a normal distribution with a mean of 60,000
mel-nik [20]

Answer:

0.018 is the required probability.              

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 60,000 miles

Standard Deviation, σ = 1500 miles

We are given that the distribution of tread life is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

P(brand will last between 56,850 miles and 57,300 miles)

P(56850 \leq x \leq 57300) = P(\displaystyle\frac{56850 - 60000}{1500} \leq z \leq \displaystyle\frac{57300-60000}{1500}) = P(-2.1 \leq z \leq -1.8)\\\\= P(z \leq -1.8) - P(z < -2.1)\\= 0.0359 - 0.0179 = 0.018= 1.8\%

P(56850 \leq x \leq 57300) = 1.8\%

0.018 is the probability a certain tire of this brand will last between 56,850 miles and 57,300 miles.

7 0
4 years ago
How much is 1 in 100,000,000 as a percentage
Morgarella [4.7K]

Answer:

The answer is 0.000.000.01

5 0
4 years ago
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