Your answer would be, <span>No, it is not a valid inference because his classmates do not make up a random sample of the students in the school</span>
Answer:
27.76 grams will be present in 500 years
Step-by-step explanation:
The given formula is , where A is the value of the substance in t years, and is the initial value
∵ The half-life is a substance is 375 years
- Substitute A by and t by 375 to find the value of k
∴
- Divide both sides by
∴
- Insert ㏑ in both sides
∴ ㏑( ) = ㏑ ( )
- Remember ㏑ ( ) = n
∵ ㏑ ( ) = 375 k
∴ ㏑( ) = 375 k
- Divide both sides by 375
∴ k ≈ -0.00185
∴
∵ 70 grams is present now
- That means the initial value is 70 grams
∴ = 70
∵ The time is 500 years
∴ t = 500
- Substitute the values of and t in the formula
∵
∴ A = 27.76
∴ 27.76 grams will be present in 500 years
I see you're probably trying to use a math editor to present this problem. Unfortunately, I'm unsure how to decipher your "-\frac {a }{8.06)." What fraction are you speaking of?
Given "<span>#-\frac { a } { 8.06} + 7.02= 18.4#," all I can say with certainty is that you could legitimately subtract 7.02 from both sides:
</span><span>#-\frac { a } { 8.06} + 7.02= 18.4#
- 7.02 = -7.02
After I've heard back from you, I'll try to help you solve the entire problem.
</span>
Answer:
B.) The interquartile range of the data is 2
Step-by-step explanation: