A = lw (Area=length x width) 7x21= 147
The area is 147.
Answer:
2pi
Step-by-step explanation:
Comparing the functions, it is found that:
- The function Kimora's travel based on Jim's travel is of: D. g(x) = f(x) + 80.
- Lonnie's function based on Kimora is: B. h(x) = g(x - 2).
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Jim's equation is of:
Kimora's equation is of:
The -55x term is common to both functions, while the constant on g is 80 more than f, thus:
Which means that the answer to the first question is given by option D.
Lonnie started traveling two hours before Kimora's, using the same equation of motion, just with the input x reduced by 2, thus:
Which means that the answer to the second question is given by option B.
A similar problem is given at brainly.com/question/24759429
Answer:
(10, -9)
Step-by-step explanation:
Xs = 5 -(0-5) = 5+5 = 10
Ys = -2 -(5-(-2)) = -2 - 7 = -9
so, the coordinates of point S => (10, -9)
h(t) = -46t² + 40t + 3
We can think this graph by t being the x-axis and h being y-axis
So we want the maximum value to y.
We know by math that the vertex of a parabola is (-b/2a, -Δ/4a)
So the y value of the vertex is -Δ/4a
Let's calculate:
Δ = b² - 4.a.c
Δ = 40² - 4.(-46).3
Δ = 2152
Yvertex = -2152/4.(-46)
Yvertex = 2152/184
Yvertex = 269/23
Now we have the value of y we need to equal it to the equation
269/23 = -46t² + 40t + 3
-46t² + 40t + 3 - 269/23 = 0
-46t² + 40t - 200/23 = 0
Δ = b² - 4.a.c
Δ = 40² - 4 . -46 . (-200/23)
Δ = 1600 - 4. -46 . (-200/23)
Δ = 0
There's 1 real root.
In this case, x' = x'':
x = (-b +- √Δ)/2a
x' = (-40 + √0)/2.-46
x'' = (-40 - √0)/2.-46
x' = -40 / -92
x'' = -40 / -92
x' = 0,43478260869565216
x'' = 0,43478260869565216
So, after approximately 0,4348 seconds the balloon will reach the highest point.
B) height after 2 seconds
h(2) = -46.2² + 40.2 + 3
h(2) = -46.4 + 80 + 3
h(2) = -184 + 83
h(2) = -101
Not sure how it's possible but it would be -101.
