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vekshin1
3 years ago
10

A triangle has side lengths 30,98,103 is if a right triangle

Mathematics
2 answers:
Alik [6]3 years ago
4 0
I cant really ay, but i think it is a right angled triangle
Over [174]3 years ago
3 0

Answer:

it is a right triangle

Step-by-step explanation:

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Can you help me answer the question please :l
liberstina [14]

27

You can find the area of a triangle with base b and height h using this formula.

A=

1

2

bh

The triangle has base b=6miles and height h=9miles.

Find the area.

A

=  

1

2

bh

=  

1

2

(6)(9)

= (3)(9)

= 27

The area of the triangle is 27 square miles.

4 0
3 years ago
When Lucas first opened his bank account, he deposited x amount of
iogann1982 [59]

Answer:

55

Step-by-step explanation:

Lucas went to the bank the first time with $55 and the second time with $55, when you add those togeother you get $110. Then he wrote a check for $116 and ended up having -$6...basically if you have $110 in all then you write a check for $116 you would have -$6 in your balance. 110-116 = -6

5 0
3 years ago
11×12=(10+1)×(10+2)what property dose this demonstrate
Natasha2012 [34]
This demonstrates the associative property
4 0
4 years ago
Read 2 more answers
There is a line through the origin that divides the region bounded by the parabola y=2x-4x^2 and the x-axis into two regions wit
shtirl [24]
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.

y = 7x - 4x² 

<span>7x - 4x² = 0 </span>

<span>x(7 - 4x) = 0 </span>

<span>x = 0, 7/4 </span>

<span>Find the area of the bounded region... </span>

<span>A = ∫ 7x - 4x² dx |(0 to 7/4) </span>

<span>A = 7/2 x² - 4/3 x³ |(0 to 7/4) </span>

<span>A = 7/2(7/4)² - 4/3(7/4)³ - 0 = 3.573 </span>

<span>Half of this area is 1.786, now set up an integral that is equal to this area but bounded by the parabola and the line going through the origin... </span>

<span>y = mx + c </span>

<span>c = 0 since it goes through the origin </span>

<span>The point where the line intersects the parabola we shall call (a, b) </span>

<span>y = mx ===> b = m(a) </span>

<span>Slope = m = b/a </span>

<span>Now we need to integrate from 0 to a to find the area bounded by the parabola and the line... </span>

<span>1.786 = ∫ 7x - 4x² - (b/a)x dx |(0 to a) </span>

<span>1.786 = (7/2)x² - (4/3)x³ - (b/2a)x² |(0 to a) </span>

<span>1.786 = (7/2)a² - (4/3)a³ - (b/2a)a² - 0 </span>

<span>1.786 = (7/2)a² - (4/3)a³ - b(a/2) </span>

<span>Remember that (a, b) is also a point on the parabola so y = 7x - 4x² ==> b = 7a - 4a² </span>
<span>Substitute... </span>

<span>1.786 = (7/2)a² - (4/3)a³ - (7a - 4a²)(a/2) </span>

<span>1.786 = (7/2)a² - (4/3)a³ - (7/2)a² + 2a³ </span>

<span>(2/3)a³ = 1.786 </span>

<span>a = ∛[(3/2)(1.786)] </span>

<span>a = 1.39 </span>

<span>b = 7(1.39) - 4(1.39)² = 2.00 </span>

<span>Slope = m = b/a = 2.00 / 1.39 = 1.44</span>

7 0
3 years ago
Hallar la ecuación de la recta qué pasa por el punto (2,3) y cuya abscisa en el origen es el doble que la ordenada en el origen
Verdich [7]
Sería 5 pues porque yo solo los agregaría
5 0
2 years ago
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