The centre of the circle is (1/2, 1) and the radius of the circle is 2 if the circle equation is x² + y² − x − 2y − 11/4 = 0
<h3>What is a circle?</h3>
It is described as a set of points, where each point is at the same distance from a fixed point (called the centre of a circle)
The question is incomplete.
The complete question is:
A circle is defined by the equation given below.
x² + y² − x − 2y − 11/4 = 0
What are the coordinates for the centre of the circle and the length of the radius?
We know the standard form of a circle:
(x - h)² + (y - k)² = r²
Here (h, k) is the centre of the circle and r is the radius of the circle
Thus, the centre of the circle is (1/2, 1) and the radius of the circle is 2 if the circle equation is x² + y² − x − 2y − 11/4 = 0
Learn more about circle here:
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Answer:
A': (4,-4)
B': (3,-8)
C': (3,-5)
Step-by-step explanation:
Translation
A (5,2)---> (4,4)
B(4,6)---> (3,8)
C(4,3)---> (3,5)
Reflection over x-axis= (x,y) to (x,-y)
A': (4,-4)
B': (3,-8)
C': (3,-5)
Hope this helps!
Brainliest?
Have a good day!
Drag 0.8 where it says 0.8. Drag the 0.62 in the middle of 0.6 and 0.7. Drag 0.27 in the middle of 0.2 and 0.3, but closer to 0.3. Drag 0.52 a little higher than 0.5. Drag 0.052 in the middle of 0 and 0.1.
A vertical line crosses the graph of it in two places. When that is true, the relation does not meet the definition of a function. A function must be single-valued for each distinct value of the independent variable.
The value of the 8 in 584 is related to the 4 because 80 is 20 times 4.
I hope this helps! :D (I believe my explanation is wrong. If it is, sorry.)