Certin, because they can be any two cards.
Answer:
i really dont know how to do this
Step-by-step explanation:
Formula is
ₙCₖ = (n!)/( k!*(n-k)! )
so ₇C₃ = (7!) / (3! * (7-3)!)
and 7! = 7 * 6 * 5 * 4 * 3 * 2 * 1
= (7 * 6 * 5 * 4 * 3 * 2 * 1)/(3 * 2 * 1 * 4!)
= (7 * 6 * 5 * 4)/(4!)
= (7 * 6 * 5 * 4)/(4 * 3 * 2 * 1)
= (7 * 6 * 5 )/(6 * 1)
= (7 * 5 )/( 1)
= 35
X1,y1 and x2,y2 are on the line
