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3 years ago

2/3 of 24 bananas = how many bananas

1 answer:

3 0

To find out what two thirds of 24 bananas will be, you first need to divided 24 by 3. The answer to this will be 8, so we therefore know that 8 in one third. To find two thirds, simply times one third (8) by two, so 8*2 is 16. From this we now know that two thirds of 24 bananas will be 16.

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What is the current value of a zero-coupon bond that pays a face value of $1,000 at maturity in 6 years if the appropriate disco

Zolol [24]

Answer:4

Step-by-step explanation:

A zero-coupon bond doesn’t make any payments. Instead, investors purchase the zero-coupon bond for less than its face value, and when the bond matures, they receive the face value.

To figure the price you should pay for a zero-coupon bond, you'll follow these steps:

Divide your required rate of return by 100 to convert it to a decimal.

Add 1 to the required rate of return as a decimal.

Raise the result to the power of the number of years until the bond matures.

Divide the face value of the bond to calculate the price to pay for the zero-coupon bond to achieve your desired rate of return.

First, divide 4 percent by 100 to get 0.04. Second, add 1 to 0.04 to get 1.04. Third, raise 1.04 to the sixth power to get 1.2653. Lastly, divide the face value of $1,000 by 1.2653 to find that the price to pay for the zero-coupon bond is $790,32.

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3 years ago

The figure shows how a leaf meets the stem of a flower to form two angles.

MrRissso [65]

Answer:

Step-by-step explanation:

because the 3x will multiply the e

24 which is 8

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3 years ago

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lana66690 [7]

Answer:

Step-by-step explanation:

i did this in middle shoool

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3 years ago

After once again losing a football game to the college'ss arch rival, the alumni association conducted a survey to see if alumni

antoniya [11.8K]

Answer:

a) The 90% confidence interval would be given (0.561;0.719).

b) $p_v =P(z>2.8)=1-P(z$

c) Using the significance level assumed $\alpha=0.01$ we see that $p_v$ so we have enough evidence at this significance level to reject the null hypothesis. And on this case makes sense the claim that the proportion is higher than 0.5 or 50%.

Step-by-step explanation:

1) Data given and notation

n=100 represent the random sample taken

X=64 represent were in favor of firing the coach

$\hat p=\frac{64}{100}=0.64$ estimated proportion for were in favor of firing the coach

$p_o=0.5$ is the value that we want to test since the problem says majority

$\alpha$ represent the significance level (no given, but is assumed)

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

p= population proportion of Americans for were in favor of firing the coach

Part a

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 90% confidence interval the value of $\alpha=1-0.9=0.1$ and $\alpha/2=0.05$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.64$

And replacing into the confidence interval formula we got:

$0.64 - 1.64 \sqrt{\frac{0.64(1-0.64)}{100}}=0.561$

$0.64 + 1.64 \sqrt{\frac{0.64(1-0.64)}{100}}=0.719$

And the 90% confidence interval would be given (0.561;0.719).

Part b

We need to conduct a hypothesis in order to test the claim that the proportion exceeds 50%(Majority). :

Null Hypothesis: $p \leq 0.5$

Alternative Hypothesis: $p >0.5$

We assume that the proportion follows a normal distribution.

This is a one tail upper test for the proportion of union membership.

The One-Sample Proportion Test is "used to assess whether a population proportion $\hat p$ is significantly (different,higher or less) from a hypothesized value $p_o$ ".

Check for the assumptions that he sample must satisfy in order to apply the test

a)The random sample needs to be representative: On this case the problem no mention about it but we can assume it.

b) The sample needs to be large enough

$np_o =100*0.64=64>10$

$n(1-p_o)=100*(1-0.64)=36>10$

Calculate the statistic

The statistic is calculated with the following formula:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o(1-p_o)}{n}}}$

On this case the value of $p_o=0.5$ is the value that we are testing and n = 100.

$z=\frac{0.64 -0.5}{\sqrt{\frac{0.5(1-0.5)}{100}}}=2.8$

The p value for the test would be:

$p_v =P(z>2.8)=1-P(z$

Part c

Using the significance level assumed $\alpha=0.01$ we see that $p_v$ so we have enough evidence at this significance level to reject the null hypothesis. And on this case makes sense the claim that the proportion is higher than 0.5 or 50%.

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3 years ago

A telephone pole 13 1/3 feet tall casts a shadow of 16 feet when a person casts a shadow of 6 feet. How tall is the person?

zmey [24]

<span>Five feet tall or 5 feet tall or 60 inches. </span>

5 0

4 years ago

Read 2 more answers