Answer:
(a)
(b) 5220 j
(c) 1740 watt
(d) 3446.66 watt
Explanation:
We have given mass m = 290 kg
Initial velocity u = 0 m/sec
Final velocity v = 6 m/sec
Time t = 3 sec
From first equation of motion
v = u+at
So
(a) We know that force is given by
F = ma
So force will be
(b) From second equation of motion we know that
We know that work done is given by
W = F s = 580×9 =5220 j
(c) Time is given as t = 3 sec
We know that power is given as
(d) Time t = 1.5 sec
So
Answer:
(a) the runner's kinetic energy at the given instant is 308 J
(b) the kinetic energy increased by a factor of 4.
Explanation:
Given;
mass of the runner, m = 64.1 kg
speed of the runner, u = 3.10 m/s
(a) the kinetic energy of the runner at this instant is calculated as;
(b) when the runner doubles his speed, his final kinetic energy is calculated as;
the change in the kinetic energy is calculated as;
Thus, the kinetic energy increased by a factor of 4.
The problem is asking the maximum separation between the telescope in the moon and mars. To tell you frankly, I have no idea how to calculate this by I research the answer which I will give to you and the clue that I just know is that the distance should be in kilometers and the telescopes diameter could affect the minimum separation between the two object. With that the answer would be 422,700 km
F force
I current
L length of wire in magnetic field
B magnetic field strength
θ angle between wire and magnetic field
if θ = 90°
Answer: D
Explanation: Gaseous composition, larger size and many moons