Y - 0 = -1(x + 3)
y = -x - 3
hope it helps
Answer:
Option 3 (7,2) is right answer.
Step-by-step explanation:
Given two equations
3x-2y=17 ... i
x-3y=1 ... ii
We can solve this by elimination.
coefficients of x are 3 and 1 with LCD = 3
Hence multiply ii equation by 3
3x-9y = 3 ... iv
3x-2y = 17 ... i
Subtract i from iv
-7y = -14
Divide by -7
y =2
Substitute in ii
x-3(2) = 1
x=7
Hence solution is (7,2)
Verify:
We can verify our solution by substituting in i and ii.
3(7)-2(2) = 17 and 7-6 =1
Verified
I am not 100 percent sure but i think you multiply and the answer is 7.75 if not then try to divid how you get 7.75 is you make 3/4 into a decimal and that becomes 0.75 them multiply by 10 and get 7.75
Answer:
2 times larger
Step-by-step explanation:
Funny, this looks like a complex graph, until you realize that the numerator can be written like (x+3)(x-9).
So really, this is a straight line f(x) = x-9.
But wait, there's a catch. x≠3, because that would divide by zero. So in your straight line, you have to draw a "hole" at (3,6)