Answer:
1. 0.55
2. 4.95
Step-by-step explanation:
450x20/1000/1000x8
= 9 megabytes/sec
the service time u = 10 megabytes per sec
ρ = 9÷10 = 0.9
1. the mean residence tr of a packet in the system
= 2-ρ/2 x u(1-ρ)
= 2-0.9/2 x 10(1-0.9)
= 0.55x1
= 0.55
2. the mean number of packets that are waiting to be processed inthe queue
= (2-p) x p/2 x (1-p)
= 2-0.9 x 0.9/2 x 1-0.9
= 1.1 *0.45 x 0.1
= 4.95
Answer:
Step-by-step explanation:
It is a linear homogeneous differential equation with constant coefficients:
y" + 4y = 0
Its characteristic equation:
r^2+4=0
r1=2i
r2=-2i
We use these roots in order to find the general solution:
Answer:
9800Joules
Step by step Explanations
Before we can set the integral up, let the upper half the aquarium be divided into horizontal slices for easy calculation
Then we will represent distance from the top of the tank as X and also
2 its thickness as ∆x
We will be working on the horizontal slices , since in the horizontal slices each drop of water in a given slice will be have the same distance from the top of the tank.
Given that An aquarium has;
Length = 8 m long,
Width = 1 m wide,
Dept =1 m deep
And ∆x m,
density of water is 1000 kg/m3
g = 9.8 m/s2
CHECK THE ATTACHMENT FOR DETAILED EXPLANATION
Answer:
3/50 7/50 40/50
Step-by-step explanation:
Ok. I'm not exactly a math wiz but I think you may be overthinking this. Experimental probability should be the probability from the experiment right. It's in the name. In chemistry if it's a well established value it's called a theoretical value or probability. So the answer should just be the probability from the said experiment. No other funky math terms are given here which clues me to the idea that it might just be this simple.