4 years ago

Determine if the statement is always, sometimes or never true. An exterior angle of a triangle is 180 degrees.

Mathematics

1 answer:

juin [17]4 years ago

7 0

the nswer is it is never true

You might be interested in

The geographic areas of California and the U.S. are 1.637×10^5 and 3.794x10^6 sq. mi., respectively. California’s population (as

olya-2409 [2.1K]

2x + 6 = 4x/2 + 12/2

To solve this, we need to transpose like terms to the same side.

2x - 4x/2 = 12/2 - 6

2x - 2x = 6 - 6

0 = 0

Since both sides are zero, it means that the equation has infinite number of solutions.

Step-by-step explanation:

8 0

3 years ago

0.7 is 10 times what number

Gemiola [76]

Your answer is 7. I hope this helps you out.

3 0

3 years ago

Read 2 more answers

Evaluate without using a calculator (x2y-3)0+x1/3-(4x)1/2 when x = 64 and y = 27. Show work.

aleksley [76]

Given:

The expression is:

$(x^2y-3)^0+x^{\frac{1}{3}}-(4x)^{\frac{1}{2}}$

To find:

The value of the given expression when $x=64$ and $y=27$ .

Solution:

We have,

$(x^2y-3)^0+x^{\frac{1}{3}}-(4x)^{\frac{1}{2}}$

Putting $x=64$ and $y=27$ , we get

$=((64)^2(27)-3)^0+(64)^{\frac{1}{3}}-(4(64))^{\frac{1}{2}}$

It can be written as

$=((64)^2(27)-3)^0+(4^3)^{\frac{1}{3}}-(4)^{\frac{1}{2}}(64)^{\frac{1}{2}}$

$=1+4-2(8)$ $[\because a^0=1,a\neq 0]$

$=5-16$

$=-11$

Therefore, the value of the given expression $-11$ when $x=64$ and $y=27$ .

4 0

3 years ago

Mrs.Chamlin earns Rs.6000 in a week.She spends Rs.250 for food and Ra.75 for transportation everyday.How much does she save in a

tia_tia [17]

Answer:

5,675

Step-by-step explanation:

she save 5,675 in a week

5 0

3 years ago

Please help me with this!!

Kaylis [27]

Answer:
2 dollars each

Step-by-step :
Since 7 - 3 is 4
And 2 fries were bought then we have to divide 4 by 2 which equals 2. So 2 dollars were each small package of fries.

8 0

3 years ago