With what you do need help?????
Note that the density of mercury is
(i) 13545 kg/m^3 at 20 deg.C
(ii) 13472 kg/m^3 at 50 deg, C
For a given mass, M kg, by using the volume at 20 deg. C, obtain
M = (13545 kg/m^3)*(0.002 m^3) = 27.09 kg .
Let V m^3 = volume at 50 deg. C
Then
(13472 kg/m^3)*(V m^3) = 27.09 kg
V = 27.09/13472 = 0.002010837 m^3
Answer:
The closest answer is A. 0.002010812 m^3
Answer:
1/3 times.
Explanation:
Let V₀ be the peak voltage .
IR ( rms ) = ( V₀ / √2 R )
R is value of resistance
IC = ( V₀ ωC / √2 )
( 1 / ωC is reactance of capacitance in ac circuit )
=
When frequency is tripled angular frequency will also be tripled
hence the ratio becomes 1/3 times.
Answer:
26 cm
Explanation:
V = Volume
R = Outer radius of the shell = 58.7 cm
r = Inner radius of the shell
g = Acceleration due to gravity = 9.81 m/s²
\rho = Density
As the shell is completely submerged
Force on shell
Weight of the shell
Equating the two equations as the forces are conserved
Inner radius of the shell is 0.561 m
The thickness of the wall is 0.587-0.561 = 0.026 m = 26 cm