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4 years ago

Solve for x -3x = 15

Mathematics

1 answer:

wlad13 [49]4 years ago

6 0

Answer:

X = -5

Step-by-step explanation:

Not really much to do.

1. Divide by -3 on both sides to get x by itself.

$\frac{-3x}{-3} = \frac{15}{-3}$

$x=-5$

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kakasveta [241]

Answer:

31/11

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3 years ago

Determine the measure of the third angle. * o 48° O 62° O 70° 132 180°

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3 years ago

System OT<br> W + b =13<br> 6.5w + 2b = 57.5

mixer [17]

Answer: w = 7, x = 6

Step-by-step explanation: Solve by substitution

W + b = 13

rewrite as b = 13 - w and substitute that value for b in the second equation

6.5w + 2b = 57.5 Then solve for w

6.5w + 2(13-w) = 57.5 . Distribute

6.5w + 26 - 2w = 57.5 . Subtract 26 from both sides. Combine like terms and simplify

6.5w - 2w = 57.5 - 26

4.5w = 31.5 Divide both sides by 4.65

w = 7 . Substitute 7 for w in the first equation and solve for b

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b = 6

6 0

3 years ago

All I've found is 1 but how do I work that out properly beaides guess and check

BaLLatris [955]

Answer:

Step-by-step explanation:

(1-x)/x=0

or, 1-x=0

or, -x=-1

or, x=1

5 0

3 years ago

Read 2 more answers

The diagram shows a 5 cm x 5 cm x 5 cm cube.

mylen [45]

Answer:

~8.66cm

Step-by-step explanation:

The length of a diagonal of a rectangular of sides a and b is

$\sqrt{a^2+b^2}$

in a cube, we can start by computing the diagonal of a rectangular side/wall containing A and then the diagonal of the rectangle formed by that diagonal and the edge leading to A. If the cube has sides a, b and c, we infer that the length is:

$\sqrt{\sqrt{a^2+b^2}^2 + c^2} = \sqrt{a^2+b^2+c^2}$

Using this reasoning, we can prove that in a n-dimensional space, the length of the longest diagonal of a hypercube of edge lengths $a_1, a_2, a_3, \ldots, a_n$ is

$\sqrt{a_1^2 + a_2^2 + a_3^2 + \ldots + a_n^2}$

So the solution here is

$\sqrt{(5cm)^2 + (5cm)^2 + (5cm)^2} = \sqrt{75cm^2} = 5\sqrt{3cm^2} \approx 5\cdot 1.732cm = 8.66cm$

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3 years ago

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