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Agata [3.3K]
3 years ago
11

A binomial probability distribution has p = .20 and n = 100.

Mathematics
2 answers:
AleksAgata [21]3 years ago
3 0

Answer:

Mean = 0.2(100) = 20

Variance = 0.2×0.8×100 = 16

Standard deviation = 4

Yes, np > 5 & nq > 5

melamori03 [73]3 years ago
3 0

Answer:

Mean = 0.2(100) = 20

Variance = 0.2×0.8×100 = 16

Standard deviation = 4

Yes, np > 5 & nq > 5

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1.75x+1.25y=2<br> 7x+5y=9<br> how many solutions does this system of equations have?
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Answer:

Step-by-step explanation:

1.75x+1.25y=2           Multiply this equation by 4

7x + 5y = 8

7x+5y=9

As you can see, the xs and ys have the same coefficient. These lines are parallel. There are NO solutions. Just to show you that, here is a graph.

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complete the square to determine the minimum or maximum value of the function defined by the expression x^2 + 4x+3
beks73 [17]

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3 years ago
What is the value of n in this equation?<br>n+ 134 = 379<br>423<br>245<br>334​
alexira [117]

Answer:

the answer to this question is 245

Step-by-step explanation:

n+134=379

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n=245

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3 years ago
Read 2 more answers
A new car battery is sold with a two-year warranty whereby the owner gets the battery replaced free of cost if it breaks down du
lara [203]

Answer:

a) 0.1587 = 15.87% probability that a battery will break down during the warranty period.

b) The expected profit of the auto store on a battery is of $15.239.

c) The expected monthly profit on batteries if the auto store sells an average of 500 batteries a month is of $7,619.50.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

The life of batteries is known to be normally distributed with a mean and a standard deviation of 40 and 16 months, respectively.

This means that \mu = 40, \sigma = 16

a. What is the probability that a battery will break down during the warranty period?

Two year warranty, that is, 24 months. This probability is the pvalue of Z when X = 24. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{24 - 40}{16}

Z = -1

Z = -1 has a pvalue of 0.1587.

0.1587 = 15.87% probability that a battery will break down during the warranty period.

b. What is the expected profit of the auto store on a battery?

1 - 0.1587 = 0.8413 probability of a profit of $20.

0.1587 probability of a loss of $10. So

E = 0.8413*20 - 0.1587*10 = 15.239

The expected profit of the auto store on a battery is of $15.239.

c. What is the expected monthly profit on batteries if the auto store sells an average of 500 batteries a month?

Multiplying the average for a battery by 500. So

15.239*500 = $7,619.50

The expected monthly profit on batteries if the auto store sells an average of 500 batteries a month is of $7,619.50.

5 0
3 years ago
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