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AveGali [126]
3 years ago
5

Pick a number...

Mathematics
2 answers:
sweet [91]3 years ago
5 0
7+3=10
10+10=20
24
12-7=5
Art [367]3 years ago
4 0
Well okay then... kinda obvious 
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line segment connecting the vertices of a hyperbola is called the ________ ________, and the midpoint of the line segment is the
Lesechka [4]

line segment connecting the vertices of a hyperbola is called the <u>transverse axis</u> and the midpoint of the line segment is the <u>center</u> of the hyperbola.

What is transverse axis and center of hyperbola ?

The transverse axis is a line segment that passes through the center of the hyperbola and has vertices as its endpoints. The foci lie on the line that contains the transverse axis. The conjugate axis is perpendicular to the transverse axis and has the co-vertices as its endpoints.

And The center of a hyperbola is the midpoint of both the transverse and conjugate axes, where they intersect. Every hyperbola also has two asymptotes that pass through its center. As a hyperbola recedes from the center, its branches approach these asymptotes.

Learn more about the transverse axis and center of hyperbola here:

brainly.com/question/28049753

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5 0
2 years ago
Rebeccas pre-k group has 2/7 of a tub of goldfish. there are 4 kids in her group. The teacher wants to give them all the same am
Hoochie [10]

Answer:

achoooo

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
A cat bed is selling 10% off the original price. The original price was $100. What is the sale price of the bed?
Tasya [4]

Answer:

90

Step-by-step explanation:

discount = original price * percent off

discount = 100(10%)

               = 100*.10 = 10

Sale price = original price - discount

                 = 100-10

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5 0
4 years ago
Please help<br> Find f(1/3) if f(n) = 3n.
kaheart [24]

Answer:

1

Step-by-step explanation:

f(n) = 3n

f(1/3)= 3*(1/3)=1

f(1/3)=1

5 0
3 years ago
Read 2 more answers
Shoutout to lester bc i know he's gonna answer this ;) !
MrMuchimi

Answer:

A (-3,9)

Step-by-step explanation:

ok easy they they us

R(2,1) and R'(-4,8)

subtract 6 from y and add 7 to y

ok lets solve for S'

S(3,2) now subtract 6 and add 7

(3,2)+(-6,7)

(-3,9)

5 0
3 years ago
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