Given exponential function
f(x)= 
Where x is the number of years
f(x) is the number of tuna in thousands
To find out when number of tuna is 50 thousand , we plug in 50 for f(x) and solve for x
Divide by 230 on both sides
Take ln on both sides
Divide by ln(0.881) on both sides
x = 
x= 12.04
Year = 1974 + 12.04 = 1986
so in 1986 there will be 50 thousand tuna.
Answer:
there is no question but i think out of a,b,c and e i think b or c
Step-by-step explanation:
sorry
Answer:
a) The equation is:
Confidence Interval = Mean ± Z score × Standard deviation/√Number of samples
b) The 98% confidence interval = (5.62784, 6.37216)
Step-by-step explanation:
a. Write down the equation you should use to construct the confidence interval for the average number of days absent per term for all the children. (10 points)
Confidence Interval = Mean ± Z score × Standard deviation/√Number of samples
b. Determine a 98% confidence interval estimate for the average number of days absent per term for all the children. (10 points)
Confidence Interval = Mean ± Z score × Standard deviation/√Number of samples
Mean = 6 days
Standard deviation = 1.6 days
Number of samples = 100
Z score of 98% confidence interval = 2.326
Confidence interval = 6 ± 2.326 × 1.6/√100
= 6 ± 2.326 × 1.6/10
= 6 ± 0.37216
= 6 - 0.37216
= 5.62784
6 + 0.37216
= 6.37216
Therefore, the 98% confidence interval = (5.62784, 6.37216)
