Answer:
3859 g
Explanation:
1 pound = 0.454 kg
therefore, 8.50 ponds = 0.454*8.50 = 3.859
to covert kilograms into grams you need to multiply it by 1000
=3.859*1000
= 3859 grams
Answer: T = 93 N
Explanation:
Assuming the pulley is ideal meaning frictionless as mentioned and also negligible mass.
ΣF = Σma
Mg - mg = Ma + ma
a = g(M - m) / (M + m)
Now looking only at the larger mass as it falls
Mg - T = Ma
T = Mg - Ma
T = Mg - Mg(M - m) / (M + m)
T = Mg(1 -(M - m) / (M + m))
T = 16(9.8)(1 - (16 - 6.7) / (16 + 6.7))
T = 93 N
or looking only at the smaller mass
T - mg = ma
T = m(g + a)
T = m(g + g(M - m) / (M + m))
T = mg(1 + (M - m) / (M + m))
T = 6.7(9.8)(1 + (16 - 6.7) / (16 + 6.7))
T = 93 N
Answer:
- it would probably snap or brake - that qustion makes no sense
Explanation:
Kepler's third law hypothesizes that for all the small bodies in orbit around the
same central body, the ratio of (orbital period squared) / (orbital radius cubed)
is the same number.
<u>Moon #1:</u> (1.262 days)² / (2.346 x 10^4 km)³
<u>Moon #2:</u> (orbital period)² / (9.378 x 10^3 km)³
If Kepler knew what he was talking about ... and Newton showed that he did ...
then these two fractions are equal, and may be written as a proportion.
Cross multiply the proportion:
(orbital period)² x (2.346 x 10^4)³ = (1.262 days)² x (9.378 x 10^3)³
Divide each side by (2.346 x 10^4)³:
(Orbital period)² = (1.262 days)² x (9.378 x 10^3 km)³ / (2.346 x 10^4 km)³
= 0.1017 day²
Orbital period = <u>0.319 Earth day</u> = about 7.6 hours.