Answer:
8, 5, 0 (B, C, D)
Step-by-step explanation:
okay so in order to solve this, first you would do 300-140 since the limit is 300 and 140 is already occupied. 300-140=160. Next, to find the number of 20-pound bags that can fit, you would do 160/20 or just 20b<_160 (<_ is less than or equal to). b<_ 8, therefore you could have anything ranging from 0b-8b. You cannot have a negative number of bags, that is just not possible, and with 10 bags, you surpass the weight limit by 40 pounds.
Answer: $945
Step-by-step explanation: 11.25x39 is 438.75 and 11.25x45 is 506.25 and you add them together which is 945
Answer:
Step-by-step explanation:
hmm idk bro thats wack
Answer:
17
Step-by-step explanation:
2 times 17=34
Answer:
there are 4725 different ways to pick the 11 players
Step-by-step explanation:
assuming that a player can only play from its position and not from the other 2 , then each defensive position is independent from the others , and since the order each player is chosen is not relevant we have that:
total combinations = possible combinations of linemen * possible combinations of linebackers * possible combinations of defensive backs = combinations of 5 linemen from 7 * combinations of 4 linebackers from 6 * combinations of 2 defensive backs from 6 = [ 7!/(5!*(7-5)!] * [ 6!/(4!*(6-4)!] * [ 6!/(2!*(6-2)!] = 7!/(2!*5!)*[ 6!/(4!*2!)]² = 4725 combinations
thus there are 4725 different ways to pick the 11 players