A fair die would have 6 sides,
Therefore, 6 different numbers has a probability to appear.
Thus, any number has 1/6 chance to appear.
Since you want a specific sequence to occur,
4 results would be (1/6)^4
Therefore the probability is 1/54
Y ÷ 4 • 3 – 6 ÷ x + 8 replace y with 24 and x with 3
24 ÷ 4 • 3 – 6 ÷ 3 + 8
6 • 3 – 6 ÷ 3 + 8
18 – 6 ÷ 3 + 8
18 - 2 + 8
16 + 8
24
The answer is C) The quotient of some number and six
The answer is: " 340 " . There are 340 nickels in 17 dollars.
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Explanation:
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There are 20 nickels in one dollar.
Since 1 dollar = $1.00 = 100 cents ; and:
1 nickel = 5 cents
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(5 cents)*x = 100 cents ; solve for "x" ; x = the number of nickels in 1 dollar;
Divide each side of the equation by "5 cents" ;
[(5 cents)*x] / (5 cents) = (100 cents) / (5 cents) ;
to get:
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x = 20 .
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There are 20 nickels in one (1) dollar.
20 nickels * 17 dollars = number of nickels in 17 dollars.
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20 * 17 = 340 nickels in 17 dollars.
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The answer is: " 340 " . There are 340 nickels in 17 dollars.
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