3x-y=2....(i)
2x-y=3.....(ii)
now adding the eqn I and ii ,
3x-y=2
2x-y=3
+ + +
5x=5
x=1
Now substituting the value of x in eqn I
3×1-y=2
3-y=2
-y=-1
y=1
(-1)^4 is = (-1)(-1)(-1)(-1)= 1
Hope this helps!
Answer:
d. 200
Step-by-step explanation:
if the second digit is above 5, you round up. if it's below 5, you round down. so 96=100, 33=30, 17=20, and 48=50.
