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vekshin1
4 years ago
10

What's the solution to 20+2x<5x+17-3x

Mathematics
2 answers:
aalyn [17]4 years ago
8 0
1 Simplify 5x+17-3x to <span>2x+17

</span><span>20+2x<2x+17

</span>2 Cancel 2x on both sides.

<span>20<17

</span>3 Since <span>20<17</span> is false, there is no solution<span>
No solution. :)

I hope this helps you understand! :D

Have a great day by the way.

</span>
<span>

</span>
Drupady [299]4 years ago
5 0
Treat it like an equation, you'll do a simple two-step rearrangement:
20+2x < 5x +17-3x -> 20+2x < 2x+17 -> 3+2x < 2x -> 3 < 0x. Now at this point in solving we run into a problem... nothing times 0 can be greater than 3, so this is undefined
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