Answer:
6(5+k)
Step-by-step explanation:
The sum of 5 and k
5+k
6 times the sum
6(5+k)
So assuming you know how to factor a normal quadratic formula, then you know that the first step is to multiply a times c and find the factors that add up to give you b. aXc (1X16) so you will be looking at factors of a positive 16.
1X16
2X8
4X4
Now the question is, "which one adds up to b?" The answer would be 4X4. Since you now know this, you can separate the quadratic into two parts.
*****Since the first x is to the fourth power both middle values will be to the second power.
(x^4+4x^2)(4x^2+16)
Then take out a GCF from each. Remember you want what is in the parenthesis to end up being the same.
x^2(x^2+4) +4(x^2+4)
Then simplify the expression
(x^2+4)(x^2+4)
You can see that they are the same, so now you can condense it inot a final answer of:
(x^2+4)^2
Hope this helps! Let me know if you still have questions.
Answer:
[1, 1]
Step-by-step explanation:
Translation → [-1, 3] moves down to [-1, 1]
Now, a <em>90°-clockwise rotation </em>is the exact same as a <em>270</em><em>°</em><em>-</em><em>counterclockwise</em><em> </em><em>rotation,</em><em> </em>and according to the <em>270°-counterclockwise </em><em>rotation</em><em> </em>[<em>90°-clockwise rotation</em>] rule, you take the y-coordinate, bring it over to your new x-coordinate, and take the OPPOSITE of the x-coordinate and set it as your new y-coordinate:
<u>Extended Rotation Rules</u>
- 270°-clockwise rotation [90°-counterclockwise rotation] >> (<em>x</em><em>,</em><em> </em><em>y</em>)<em> </em>→<em> </em>(<em>-</em><em>y</em><em>,</em><em> x</em>)
- 270°-counterclockwise rotation [90°-clockwise rotation] >> (<em>x</em><em>,</em><em> </em><em>y</em>) → (<em>y</em><em>,</em><em> </em><em>-</em><em>x</em>)
- 180°-rotation >> (<em>x, y</em>) → (<em>-</em><em>x</em><em>,</em><em> </em>-y)
Then, you perform your rotation:
270°-counterclockwise rotation [90°-clockwise rotation] → [-1, 1] moves to [1, 1]
I am joyous to assist you anytime.
Lol lol lol. 1st draw this out.
1. should be the asa tct because there is 1 side that is given that is equal(ad and cd, but it could also be bd, but idk if you learned that yet) , and 2 angles are given that are equal (bda and bdc, bac, acb)
2)CPCTC (congruent parts of congruent triangles are congruent.
The second question is (x-5)(2x+7)