F = ma
F 1500N
m = 100 kg
1500 = 100 * a
Solve for a.
The following formula gives the connection between the force, the mass and the acceleration:
F=ma
In our case we know the force and the mass. F=20N and m=10kg
a=F/m
a=20m/s^2/10=2<span>m/s^2</span>
<span>AS T1,T2,T3 are the tensions in the ropes,assuming that there are Three blocks of mass 3m, 2m, and m.T3 is the string between 3m and 2m,T2 is the string between 2m and m ,T1 is the string attached to m thus T1 pulls the whole set of blocks along, so it must be the largest. T2 pulls the last
two masses, but T3 only pulls the last mass, so T3 < T2 < T1.</span>
We are given the mass of an <span>aluminum sculpture which is 145 kg and a horizontal force equal to 668 Newtons. The coefficient of friction can be determined by dividing the horizontal force by the weight of the object. In this case, 668 N / 145 * 9.8 equal to coeff of friction of 0.47</span>
because its has energy and uses it natural energy from the ground
