Answer:
461.54 kg/h
Explanation:
First lets calculate the mass flow of the dry product:
Md=1000 kg/h*(1-0.58) = 420 kg/h
The mass flow of the moist final product is then:
Mm= 420 kg/h /(1-0.22) = 538.46 kg/h
The water to be evaporated is then the difference between the feed and the product.
W= 1000 kg/h - 538.46 kg/h = 461.54 kg/h
Answer:
Thomson to decide that atoms were not indivisible, in reality are actually composed of smaller parts? Thomson used a scanning tunneling micrograph to capture images of atoms. Thomson used a beam of negatively charged particles. Thomson used only the experimental results of other scientists
Explanation:
Answer:
Dissociation of O-H bond is highly favorable in p-cyanobenzoic acid resulting to higher acidity as compared to m-cyanobenzoic acid.
Explanation:
In p-cyanobenzoic acid, adjacent carbon to carboxyl group (-COOH) gets a partial positive charge due to electron withdrawing resonating effect of carboxyl group as compared to m-cyanobenzoic acid.
Due to this partial positive charge on carbon atom in p-cyanobenzoic acid, O-H bond in -COOH group remains highly polarized towards oxygen atom. Hence, dissociation of O-H bond is highly favorable in p-cyanobenzoic acid resulting to higher acidity as compared to m-cyanobenzoic acid.
Resonance structures are given below.
When Be(OH)₂ dissolves it dissociates into the following ions
Be(OH)₂ --> Be²⁺ + 2OH⁻
molar solubility is the number of moles that dissolve in 1 L of solution
If the molar solubility of Be(OH)₂ is 'x', molar solubility of Be²⁺ and OH⁻ ions are x and 2x respectively.
ksp is solubility constant for Be(OH)₂
ksp = [Be²⁺][OH⁻]²
6.92 * 10⁻²² = [x][2x]²
4x³ = 6.92 * 10⁻²²
x³ = 1.73 * 10⁻²²
x = 5.57 * 10⁻⁸ mol/L
molar solubility of Be(OH)₂ is 5.57 * 10⁻⁸ mol/L