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3 years ago

Sunspots are cooler than the surrounding solar surface because

Physics

1 answer:

irina1246 [14]3 years ago

6 0

Answer:

Because the convection process stops and hotter plasma doesn't replace the cooler plasma on the surface

Explanation:

Sun spots are the darker and relatively cooler regions on the surface of the Sun (photosphere). Their temperature is around 1000° C lower than the Sun's surface.

Reason: The Sun's surface is granulated because of the convection process happening in the layer just below the photosphere. Because of the convection, hotter plasma comes on the surface, release energy, and then gets replaced by the hotter plasma. Just like tea or water boils. The places where magnetic field line enter into and exit from the surface, this convection process stops. Thus these area starts getting cooler and appear black in color.

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3 years ago

A point charge Q is placed at the center of a conducting spherical shell (inner radius a, outer radius b). What is the electric

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Answer:

a) $E=\dfrac{Q}{\varepsilon _o\times 4\pi r^2}\ N/C$

b)E=0

c) $E=\dfrac{Q}{\varepsilon _o\times 4\pi r^2}\ N/C$

Explanation:

Given that

A point charge Q is placed at the center of a conducting spherical shell .Due to this - Q charge will induce on the inner sphere surface and +Q will induce on the outer sphere surface .

a) r < a

At a radius r ,from gauss theorem

$E.ds=\dfrac{q_i}{\varepsilon _o}$

$E\times 4\pi r^2=\dfrac{Q}{\varepsilon _o}$

$E=\dfrac{Q}{\varepsilon _o\times 4\pi r^2}\ N/C$

b) a < r < b

$E.ds=\dfrac{q_i}{\varepsilon _o}$

The total induce in this surface = - Q+ Q =0

$E.ds=\dfrac{0}{\varepsilon _o}$

E = 0

c) r > b

$E.ds=\dfrac{q_i}{\varepsilon _o}$

$E\times 4\pi r^2=\dfrac{Q}{\varepsilon _o}$

$E=\dfrac{Q}{\varepsilon _o\times 4\pi r^2}\ N/C$

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Explanation: