It’s B. Require a small force over a long distance
Answer:
The correct answer is B)
Explanation:
When a wheel rotates without sliding, the straight-line distance covered by the wheel's center-of-mass is exactly equal to the rotational distance covered by a point on the edge of the wheel. So given that the distances and times are same, the translational speed of the center of the wheel amounts to or becomes the same as the rotational speed of a point on the edge of the wheel.
The formula for calculating the velocity of a point on the edge of the wheel is given as
= 2π r / T
Where
π is Pi which mathematically is approximately 3.14159
T is period of time
Vr is Velocity of the point on the edge of the wheel
The answer is left in Meters/Seconds so we will work with our information as is given in the question.
Vr = (2 x 3.14159 x 1.94m)/2.26
Vr = 12.1893692/2.26
Vr = 5.39352619469
Which is approximately 5.39
Cheers!
According to the properties you provided, that should be metals.
Answer:
v2 = 12m/s
Explanation:
To find the velocity of water in the lower tube you use the following formula:
(1)
v1: velocity in the first tube
v2: velocity in the second tube
A1: area of the first tube
A2: area of the second tube
From the expression (1) you can obtain the velocity v2, that is the velocity of water in the second tube:
you replace the values of the parameter in order to calculate v2:
hence, the velocity of the water is 12m/s