The hypothenuse of a right triangle inscribed in a circle will cross through the midpoint of the circle
hence you know the diameter of the circle is 5
C= pi*d
I think it would be twelve because it is a multiple of 3 and a sum of 4
The size of angle BAJ in the given regular polygons is 84⁰.
The given parameters;
- regular hexagon = ABCDEF = 6 sides
- regular pentagon = AJFGH = 5 sides
Each interior angles of a regular hexagon is calculated as follows;
Each interior angles of a regular pentagon is calculated as follows;
The size of angle BAJ is calculated as follows;
Thus, the size of angle BAJ in the given regular polygons is 84⁰.
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-2
7*-2= -14
-14+35 = 21 which can also mean 35-14 = 21
The answer is 1. f(a) = –2a^2 – 5a + 4. If a = -3, then to find f(-3) we
have to substitute a in the general formula. f(a) = –2a^2 – 5a + 4 = -2
* a^2 – 5 * a + 4. Substitute a with -3. f(-3) = –2 * (-3)^2 – 5 * (-3)
+ 4 = -2 * 9 - (-15) + 4 = -18 + 15 + 4 = 1