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dybincka [34]
3 years ago
12

Angles α and β are the two acute angles in a right triangle. Use the relationship between sine and cosine to find the value of β

if β > α.
sin(x/2+20)=cos(2x-25/2)


A) 25°
B) 33°
C) 36.5°
D) 53.5°

HINT: Sine and cosine of complementary angles are related
Mathematics
1 answer:
igomit [66]3 years ago
5 0

Answer:

D) 53.5°

Step-by-step explanation:

Sine and cosine of complementary angles are equal:

sin θ = cos(90 − θ)

sin(x/2 + 20) = cos(2x − 25/2)

cos(90 − (x/2 + 20)) = cos(2x − 25/2)

90 − (x/2 + 20) = 2x − 25/2

90 − x/2 − 20 = 2x − 25/2

165/2 = 5x/2

5x = 165

x = 33

x/2 + 20 = 36.5

2x − 25/2 = 53.5

Since β > α, β = 53.5°.

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The proof for the product property of logarithms requires simplifying the expression logb(bx y) to x y. Which property is used t
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You can use the properties of logarithm to derive the simplified form of the given expression.

The simplification of the given expression requires the given below properties of logarithm

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<h3>What is logarithm and some of its useful properties?</h3>

When you raise a number with an exponent, there comes a result.

Lets say you get

a^b = c

Then, you can write 'b' in terms of 'a' and 'c' using logarithm as follows

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Some properties of logarithm are:

log_a(b) = log_a(c) \implies b = c\\\\\log_a(b) + log_a(c) = log_a(b \times c)\\\\log_a(b) - log_a(c) = log_a(\frac{b}{c})\\\\log_a(b^c) = c \times log_a(b)\\\\log_b(b) = 1

<h3>Using the above properties, to get to the simplified form of the given expression</h3>

The given expression is

log_b(b^{x+y})

Using the property log_a(b^c) = c \times log_a(b)\\\\, we get

log_b(b^{x+y}) = (x+y)\times log_b(b)

Using the property log_b(b) = 1, we get

log_b(b^{x+y}) = (x+y)\times log_b(b) = (x+y) \times 1 = x + y

Thus,

The simplification of the given expression requires the given below properties of logarithm

  • log_a(b^c) = c \times log_a(b)\\\\
  • log_b(b) = 1

Learn more about logarithms here:

brainly.com/question/20835449

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