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Romashka [77]
3 years ago
9

If you wanted to view data in reports by different user categories such as Bronze, Gold, and Platinum status levels, what Google

Analytics feature would you set up to collect this data?
A. Customer Filter
B. Customer Dimension
C. Custom Metric
D. Event Tracking
Mathematics
1 answer:
mixas84 [53]3 years ago
7 0

Answer:

B. Customer Dimension

Step-by-step explanation:

Custom dimensions is used to collect and analyze data that Analytics doesn't capture. You can send value to custom dimensions with a variable that pulls data from web page or use layer to pass specific values.

If you want to view data by different user such as Bronze , Gold , Platinum level Google Analytics feature set up the Custom Dimensions to collect the data.

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I cant answer without a pic ture plz snip it out or screen shot thx :)
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Guys I am going to run out of points. Help with 19?<br> I don't need an explanation.
nasty-shy [4]

Answer:

A.) 20x + 2y = 500

B.) y-intercept = 250; its meaning is how many boxes of pencils they started with.

C.) x-intercept = 25; How many T-shirts they can sell at most

Step-by-step explanation:

2y - 500 = -20x

20x + 2y - 500 = 0

20x + 2y = 500

y-intercept = 250; its meaning is how many boxes of pencils they started with.

20x + 2y = 500

20(0) + 2y = 500

2y = 500

2y/2 = 500/2

y = 250

x-intercept = 25; How many T-shirts they can sell at most

20x + 2y = 500

20x + 2(0) = 500

20x = 500

20x/20 = 500/20

x = 25

4 0
3 years ago
21x21..........................................
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441

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3 years ago
Identify the domain and range of the relation.
Fudgin [204]

Answer:

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Step-by-step explanation:

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3 years ago
Solve the given initial-value problem. The DE is a Bernoulli equation.
mario62 [17]

Your solution seems fine. What does the rest of the error message say?

\displaystyle y^{1/2}\frac{\mathrm dy}{\mathrm dx} + y^{3/2} = 1

Substitute

z(x)=y(x)^{3/2} \implies \dfrac{\mathrm dz}{\mathrm dx}=\dfrac32y(x)^{1/2}\dfrac{\mathrm dy}{\mathrm dx}

to transform the ODE to a linear one in <em>z</em> :

\displaystyle \frac23\frac{\mathrm dz}{\mathrm dx} + z = 1

Divide both sides by 2/3 :

\displaystyle \frac{\mathrm dz}{\mathrm dx} + \frac32z = \frac32

Multiply both sides by the integrating factor, e^{3x/2} :

\displaystyle e^{3x/2}\frac{\mathrm dz}{\mathrm dx} + \frac32 e^{3x/2}z = \frac32 e^{3x/2}

Condense the left side into the derivative of a product :

\displaystyle \frac{\mathrm d}{\mathrm dx}\left[e^{3x/2}z\right] = \frac32 e^{3x/2}

Integrate both sides and solve for <em>z</em> :

\displaystyle e^{3x/2}z = \frac32 \int e^{3x/2}\,\mathrm dx \\\\ e^{3x/2}z = e^{3x/2} + C \\\\ z = 1 + Ce^{-3x/2}

Solve in terms of <em>y</em> :

y^{3/2} = 1 + Ce^{-3x/2}

Given that <em>y</em> (0) = 16, we have

16^{3/2} = 1 + Ce^0 \implies C = 16^{3/2}-1 = 63

so that the particular solution is

\boxed{y^{3/2} = 1 + 63e^{-3x/2}}

7 0
2 years ago
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