3.9 grams CaCO3
The mass of 2.0 L of water with a density of 1.00 g/ml is 2000 grams.And 1 ppm of that is 2000 / 1000000 = 0.002 grams. So just multiply by the ppm of CaCO3, giving 0.002 g * 1.95x10^3 = 3.90 grams.
Since the least accurate datum we have is 2 significant figures, the result should be rounded to 2 significant figures, giving 3.9 grams.
Answer:
Explanation:
The surface soil, or topsoil layer (O and A horizon in Figure 1–2), usually contains less clay, but more organic matter and air, than the lower soil layers. Topsoil is usually more fertile than the other layers and has the greatest concentration of plant roots.
3 and 4 because the other two answers are different species.
Answer:
The answer is neopentyl alcohol. (CH₃)₃C-CH₂-OH
Explanation:
This alcohol cannot be synthesized by the hydroboration–oxidation of an alkene since the reaction of hydroboration–oxidation go through steps that involved the addition of BH₃ into the original structure. In the case of neopentyl alcohol, if we carry out retro synthetic by the hydroboration–oxidation, we will find the original alkene is (CH₃)₃C=CH₂ which is impossible since the center carbon atom has 5 bonds.
The condition for hydroboration–oxidation reaction is that the alkene must have the structure of R-CH=CH₂