Answer:
the first one is -4.6
Step-by-step explanation:
1. First, you must find the constant of variation (k). The problem indicates that t<span>he base of each triangle varies inversely with the height. So, this can be represented as below:
</span>
B=k/H
B is the base of the triangle (B=10).
H is the height of the triangle (H=6).
k is the constant of variation.
2. When you clear "k", you obtain:
B=k/H
k=BxH
k=10x6
k=60
3. Now, you have:
B=60/H
4. You can give any value to "H" and you will obtain the base of the second triangle.
5. If H=12, then:
B=60/H
B=60/12
B=5
6. Therefore, <span>the possible base and height of a second triangle is:
</span>
B=5
H=12
Answer:
1240.4 mm²
Step-by-step explanation:
SA of Pentagonal pyramid:
(as)(5/2) + (sl)(5/2)
↑ ↑
base area lateral area
_____________________
a: apothem (in-radius) length, s: side length.
l: slant height.
______________________
Since we are already given the base area which is 440.4 mm². All we need to do is find the lateral area and add both areas together.
Given that the triangular face of the lateral part has a side/base length of 16mm, and a 20mm slant height.
A triangle has an area of ½bh and since there are 5 of these faces total, (5)(½bh) = (5/2)(bh). In a three dimensional perspective, b will be s and h will be l so (sl)(5/2).
With this information the surface area is:
(16)(20)(5/2)mm + (440.4 mm²) →
800 mm² + 440.4 mm² =
1240.4 mm²
Answer:
-8x + 5y + 4
Step-by-step explanation:
- 6x + 5y - 2x + 4 Group like terms
-6x - 2x + 5y + 4
= - 8x + 5y + 4